document.write( "Question 168889: Using Substitution
\n" ); document.write( "4x + 2y = 1
\n" ); document.write( "2x + 3y = .70\r
\n" ); document.write( "\n" ); document.write( "Solving for X in the first problem
\n" ); document.write( "4x + 2y - 2y = 1 - 2y
\n" ); document.write( "4x = 1-2y
\n" ); document.write( "4x/4 = (1-2y)/4
\n" ); document.write( "x = (1 - 2y)/4\r
\n" ); document.write( "\n" ); document.write( "Substitute x into first equation (this is where I get lost)
\n" ); document.write( "2(1-2y/4) + 3y = .70
\n" ); document.write( "the example on this website says it should be 2(1+2y)/4+3y=.70, but if x = (1-2y)/4, how can you just change it to the 1+2y? Then also how do I solve the problem? If you could give me step by step with explanations so I understand that would be very helpful. This is my calculations:\r
\n" ); document.write( "\n" ); document.write( "2-4y/4 + 3y = .70 (multiplied 2 by everything in parentheses)
\n" ); document.write( "2-y+3y=.70 (4's cancel eachother out)
\n" ); document.write( "2+2y=.70 (3y minus 1y = 2y)
\n" ); document.write( "2+2y/2 = .70/2 (divide both sides by 2)
\n" ); document.write( "1+y = .35
\n" ); document.write( "y = .35 - 1 (subtract 1 from each side)
\n" ); document.write( "y = -.65
\n" ); document.write( "
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Algebra.Com's Answer #124574 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
You're on the right track.
\n" ); document.write( "Watch the parentheses though, they got you in trouble in the next line.
\n" ); document.write( "\"2%28%281-2y%29%2F4%29+%2B+3y+=+.70\"
\n" ); document.write( "\"%281-2y%29%2F2%2B3y=0.70\"
\n" ); document.write( "\"%281-2y%29%2B6y=1.40\"Multiply both sides by 2 to get rid of denominators.
\n" ); document.write( "\"1%2B4y=1.40\"
\n" ); document.write( "\"4y=0.40\"
\n" ); document.write( "\"y=0.1\"
\n" ); document.write( "Then from above
\n" ); document.write( "\"x+=%281+-+2y%29%2F4\"
\n" ); document.write( "\"x=%281-.2%29%2F4\"
\n" ); document.write( "\"x=0.8%2F4\"
\n" ); document.write( "\"x=0.2\"\r
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