document.write( "Question 168889: Using Substitution
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document.write( "4x + 2y = 1
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document.write( "2x + 3y = .70\r
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document.write( "Solving for X in the first problem
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document.write( "4x + 2y - 2y = 1 - 2y
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document.write( "4x = 1-2y
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document.write( "4x/4 = (1-2y)/4
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document.write( "x = (1 - 2y)/4\r
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document.write( "Substitute x into first equation (this is where I get lost)
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document.write( "2(1-2y/4) + 3y = .70
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document.write( "the example on this website says it should be 2(1+2y)/4+3y=.70, but if x = (1-2y)/4, how can you just change it to the 1+2y? Then also how do I solve the problem? If you could give me step by step with explanations so I understand that would be very helpful. This is my calculations:\r
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document.write( "2-4y/4 + 3y = .70 (multiplied 2 by everything in parentheses)
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document.write( "2-y+3y=.70 (4's cancel eachother out)
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document.write( "2+2y=.70 (3y minus 1y = 2y)
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document.write( "2+2y/2 = .70/2 (divide both sides by 2)
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document.write( "1+y = .35
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document.write( "y = .35 - 1 (subtract 1 from each side)
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document.write( "y = -.65
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Algebra.Com's Answer #124574 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! You're on the right track. \n" ); document.write( "Watch the parentheses though, they got you in trouble in the next line. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then from above \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |