document.write( "Question 23705: Please help me solve these equations: Simplify: (2X 2 yz 2)(X 2 y 2 z 2) 3=\r
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document.write( "the numbers that are one space away are exponents.\r
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document.write( "2. (f/3) 3\r
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document.write( "3. (3/5) -2 \n" );
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Algebra.Com's Answer #12454 by rapaljer(4671) You can put this solution on YOUR website! 1. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When you raise a power to a power, you multiply the exponents. This should give you: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, when you multiply with the same base number you add exponents: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The negative exponent means to take the reciprocal of the fraction: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, just square the numerator and square the denominator.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |