document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168890>Question 168890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the point on the y-axis that is equidistant from (6,1) (-2,-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124524 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124524\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the point on the y-axis that is equidistant from (6,1) (-2,-3)<BR>\n" );
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document.write( "The point must have the form (0,y)<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "distance^2 = distance^2<BR>\n" );
document.write( "(6-0^2 + (y-6)^2 = (0--2)^2 + (y--30^2\r<BR>\n" );
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document.write( "36 + y^2 -12y + 12 = 4 + y^2 +6y + 9\r<BR>\n" );
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document.write( "48 + y^2 - 12y = 13 + y^2 + 6y\r<BR>\n" );
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document.write( "18y = 35<BR>\n" );
document.write( " y = 35/18<BR>\n" );
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document.write( "Ans: (0, 35/18)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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