document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168813>Question 168813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having a hard time figuring out this literal equation 2y-2/3x+6=0 for y.<BR>\n" );
document.write( "How do you get an answer for y? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124495 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y - 2/3x + 6 = 0<BR>\n" );
document.write( "add 2/3x to, and subtract 6 from, both sides of equation:<BR>\n" );
document.write( "2y = 2/3x - 6<BR>\n" );
document.write( "divide both sides of equation by 2:<BR>\n" );
document.write( "y = 2/6x - 3<BR>\n" );
document.write( "-----<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );