document.write( "Question 168836This question is from textbook Prentice Hall Algebra 2 with Trigonometry
\n" ); document.write( ": Please help me solve this equation: \r
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\n" ); document.write( "\n" ); document.write( "numeric word problem using 3 equations.\r
\n" ); document.write( "\n" ); document.write( "The sum of three number is 105. The third is 11 less than 10 times the second. Twice the first is 7 more than three times the second. Find the Numbers
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Algebra.Com's Answer #124492 by gonzo(654)\"\" \"About 
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let a = first number.
\n" ); document.write( "let b = second number.
\n" ); document.write( "let c = third number.
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\n" ); document.write( "sum of 3 numbers is 105
\n" ); document.write( "a + b + c = 105
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\n" ); document.write( "third number is 11 less than 10 times the second.
\n" ); document.write( "c = 10*b - 11
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\n" ); document.write( "twice the first number is 7 more than 3 times the second.
\n" ); document.write( "2*a = 3*b + 7
\n" ); document.write( "a = (3*b+7)/2
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\n" ); document.write( "start with:
\n" ); document.write( "a + b + c = 105
\n" ); document.write( "substitute for a:
\n" ); document.write( "(3*b+7)/2 + b + c = 105
\n" ); document.write( "substitute for c:\"
\n" ); document.write( "(3*b+7)/2 + b + 10*b - 11 = 105
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\n" ); document.write( "equation is now in terms of b and can be solved.
\n" ); document.write( "expand all terms by removing parentheses:
\n" ); document.write( "3*b/2 + 7/2 + b + 10*b - 11 = 105
\n" ); document.write( "multiply both sides of equation by 2:
\n" ); document.write( "3*b + 7 + 2*b + 20*b - 22 = 210
\n" ); document.write( "combine like terms:
\n" ); document.write( "25*b - 15 = 210
\n" ); document.write( "add 15 to both sides of equation:
\n" ); document.write( "25*b = 225
\n" ); document.write( "divide both sides of equation by 25:
\n" ); document.write( "b = 9
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\n" ); document.write( "if b = 9, then:
\n" ); document.write( "(3*b+7)/2 = (27+7)/2 = 34/2 = 17 = a
\n" ); document.write( "and:
\n" ); document.write( "10*b - 11 = 90 - 11 = 79 = c
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\n" ); document.write( "you have:
\n" ); document.write( "a = 17
\n" ); document.write( "b = 9
\n" ); document.write( "c = 79
\n" ); document.write( "total = 105
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\n" ); document.write( "total = a + b + c = 79 + 9 + 17 = 88 + 17 = 105 (ok)
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\n" ); document.write( "c = 10*b - 11 becomes:
\n" ); document.write( "c = 10*9 - 11 = 90 - 11 = 79 (ok)
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\n" ); document.write( "a = (3*b+7)/2 becomes:
\n" ); document.write( "a = (3*9+7)/2 = (27+7)/2 = 35/2 = 17 (ok)
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