document.write( "Question 168587: Factor:
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document.write( "1.4x^2+12+9\r
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document.write( "Factor by using trial factors:
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document.write( "1. 4y2+15y+9\r
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document.write( "Factor by grouping:
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document.write( "1. 12a^2+8a-28
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document.write( "2. 2y^4+20y^3+18y^2\r
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document.write( "Factor:
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document.write( "1. a(x+4)+11(x+4) \n" );
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Algebra.Com's Answer #124484 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Factor: \n" ); document.write( "1.4x^2 + 12x + 9 \n" ); document.write( "Note that the 4 and the 9, see if it is a perfect square \n" ); document.write( "(2x + 3)(2x + 3) \n" ); document.write( ": \n" ); document.write( "Factor by using trial factors: \n" ); document.write( "1. 4y^2 + 15y + 9 \n" ); document.write( "We know that the factors of 9 are probably 3*3, the coefficients of x \n" ); document.write( " have to be different from the previous problem \n" ); document.write( "(4x+3)(x+3) \n" ); document.write( ": \n" ); document.write( "Factor by grouping: \n" ); document.write( "1. 12a^2 + 8a - 28 \n" ); document.write( "I can't seem to get this one to factor at all\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. 2y^4 + 20y^3 + 18y^2 \n" ); document.write( "2y^2(y^2 + 10y + 9) \n" ); document.write( "2y^2(y^2 + 9y + y + 9) \n" ); document.write( "2y^2(y^2 + 9y) + 2y^2(y + 9) \n" ); document.write( "2y^3(y + 9) + 2y^2(y + 9) \n" ); document.write( "(2y^3 + 2y^2)(y + 9) \n" ); document.write( "2y^2(y + 1)(y + 9) \r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "Factor: \n" ); document.write( "1. a(x+4)+ 11(x+4) \n" ); document.write( "Factor out (x+4) \n" ); document.write( "(x+4)(a+11) \n" ); document.write( " |