document.write( "Question 168829: find 4 consecutive intergers such that the sum of the first three exceeds the 4th by 18. I can not figure out how to write out the problem to solve it.\r
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document.write( "x+x+2+x+4=x+6-18\r
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document.write( "is that correct \n" );
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Algebra.Com's Answer #124478 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! find 4 consecutive intergers such that the sum of the first three exceeds the 4th by 18. I can not figure out how to write out the problem to solve it. \n" ); document.write( "x+x+2+x+4=x+6-18 \n" ); document.write( "is that correct \n" ); document.write( "------------------ \n" ); document.write( "It says integers, not even integers. And, the sum exceeds the 4th, so add 18 to the 4th, not subtract. \n" ); document.write( "------------ \n" ); document.write( "So x + x+1 + x+2 = x+3 + 18 \n" ); document.write( "3x+3 = x+21 \n" ); document.write( "2x = 18 \n" ); document.write( "x = 9 (the 1st) \n" ); document.write( "Check: \n" ); document.write( "9+10+11 = 30 \n" ); document.write( "12 + 18 = 30\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |