document.write( "Question 168829: find 4 consecutive intergers such that the sum of the first three exceeds the 4th by 18. I can not figure out how to write out the problem to solve it.\r
\n" ); document.write( "\n" ); document.write( "x+x+2+x+4=x+6-18\r
\n" ); document.write( "\n" ); document.write( "is that correct
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Algebra.Com's Answer #124470 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
your on the right track but this is 4 consecutive integers not 4 consecutive odd or even integers.....so x,x+1,x+2,x+3\r
\n" ); document.write( "\n" ); document.write( "x+x+1+x+2=x+3+18\r
\n" ); document.write( "\n" ); document.write( "3x+3=x+21\r
\n" ); document.write( "\n" ); document.write( "2x+18\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=9%29\" so integers are 9,10,11,12
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