document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168792>Question 168792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you find the exact coordinates of the vertex for the following quadration function?\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-x%281%2F2x-12%29-1%2F10 ALIGN=MIDDLE  ALT=\"y=-x%281%2F2x-12%29-1%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124447 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=-x(1/2x-12)-1/10<BR>\n" );
document.write( "y = (1/2)x^2 - 12x - (1/10)\r<BR>\n" );
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document.write( "The vertex will occur when x = -b/2a<BR>\n" );
document.write( "x = 12/(2(1/2)) = 12<BR>\n" );
document.write( "f(12) = (1/2)(12^2) -12*12 - (1/10)<BR>\n" );
document.write( "f(12) = 72 - 144 - (1/10)<BR>\n" );
document.write( "f(12) = -72.1<BR>\n" );
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document.write( "Vertex: (12 , -72.1)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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