document.write( "Question 168786: I asked the same question ealier and got an answer to try it instead of helping. Can someone please help me find what I am doing wrong. \r
\n" );
document.write( "\n" );
document.write( "y^2-6y+9\r
\n" );
document.write( "\n" );
document.write( "I got(y-3)^2 but I dont come out to the same thing when I plug in the answer I dont get the +9. I also came up with(y+3)^2 but still dont get -6y. \n" );
document.write( "
Algebra.Com's Answer #124437 by Electrified_Levi(103)![]() ![]() ![]() You can put this solution on YOUR website! Hi, Hope I can help, \n" ); document.write( ". \n" ); document.write( "If you are wanting us to solve this quadratic equation, here is how you do it. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The easiest way you can solve this is by factoring, in this case we can \n" ); document.write( ". \n" ); document.write( "First we need to write the \"y\"'s in parentheses \n" ); document.write( ". \n" ); document.write( "It is only \"y\" squared so there will be two \"y\"'s \n" ); document.write( ". \n" ); document.write( "( y )(y ) \n" ); document.write( ". \n" ); document.write( "Next, we need to find the rest of the factors of this quadratic \n" ); document.write( ". \n" ); document.write( "If the factors of the third term, in this case \"9\", add up to the middle term( in this case (-6)), it can be factored \n" ); document.write( ". \n" ); document.write( "factors of \"9\" added together \n" ); document.write( ". \n" ); document.write( "(9) + (1) = 10 \n" ); document.write( ". \n" ); document.write( "(-9) + (-1) = (-10) \n" ); document.write( ". \n" ); document.write( "(3) + (3) = 6 \n" ); document.write( ". \n" ); document.write( "(-3) + (-3) = (-6) \n" ); document.write( ". \n" ); document.write( "The last pair of factors add up to the middle term \n" ); document.write( ". \n" ); document.write( "Now we will put the factors in the parentheses with the \"y\"'s \n" ); document.write( ". \n" ); document.write( "( y )(y ) = (y - 3 )(y - 3 ) \n" ); document.write( ". \n" ); document.write( "This is the factored quadratic \n" ); document.write( ". \n" ); document.write( "( y - 3 )(y - 3 ) = 0, you can check by using the FOIL method ( First, Inner, Outer, Last ) \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " now we take each of the factors and have them equal \"0\", then solve for \"y\" \n" ); document.write( ". \n" ); document.write( "First factor = ( y - 3 ) \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "your answer is \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can also use the quadratic formula, for every quadratic equation, make sure your equation is in the form \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "a = 1 \n" ); document.write( ". \n" ); document.write( "b = -6 \n" ); document.write( ". \n" ); document.write( "c = 9 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Your answer is \n" ); document.write( ". \n" ); document.write( "Hope I helped, Levi \n" ); document.write( " |