document.write( "Question 23655: This is a quadratic function word problem. \r
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document.write( "Solve for maximum height and graph.\r
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document.write( "If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time, given by s(t) = -16t^2 + 54t. Graph this function for 0 ≤ t ≤ 4. What is the maximum height reached by the ball?\r
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document.write( "This problem is very confusing to me and any help will be greatly appreciated. \n" );
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Algebra.Com's Answer #12442 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! First: The general form of the equation for the height as a function of time of an object propelled upwards is given by: \n" ); document.write( "\n" ); document.write( "In your problem, since the ball (object) is propelled from the ground, the initial height (ho) is zero and the initial velocity of the ball is given as 64 feet/second so vo = 64. Your equation should read: \n" ); document.write( " \n" ); document.write( "The graph looks like this: \n" ); document.write( " \n" ); document.write( "Since the curve is a parabola and it opens downward, the maximum height is to be found at the vertex of the parabola. \n" ); document.write( "The x-coordinate (this really corresponds to t in your equation) is given by: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "To find the value of the height at this time, substitute t=2 into the original equation and solve for s.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |