document.write( "Question 168767: 2x
\n" ); document.write( "e = 8\r
\n" ); document.write( "\n" ); document.write( "not sure how to type it but e raised to the 2x = 8
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Algebra.Com's Answer #124419 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"e%5E%282x%29=8\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28e%5E%282x%29%29=ln%288%29\" Take the natural log of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2Aln%28e%29=ln%288%29\" Rewrite the left side using the identity \"ln%28x%5Ey%29=y%2Aln%28x%29%29\". In other words, pull down the exponent and place it in front of the \"ln\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%281%29=ln%288%29\" Take the natural log of \"e\" to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"2x=ln%288%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"x=ln%288%29%2F2\" Divide both sides by 2 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=ln%288%29%2F2\" which approximates to \"x=1.03972\"
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