document.write( "Question 23695: 1/(x-3)+ 7 = x/(x-3) solve for x\r
\n" ); document.write( "\n" ); document.write( "The answer is 10/3, how are they getting there????
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Algebra.Com's Answer #12441 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Multiply both sides of the equation by the LCD which is (x-3)\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28x-3%29%2B+7+=+x%2F%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%2A%281%2F%28x-3%29%29%2B+7%2A%28x-3%29++=%28x-3%29%2A%28+x%2F%28x-3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "The x-3 divides out in the first and last fractions leaving :\r
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\n" ); document.write( "\n" ); document.write( "\"1+%2B+7%28x-3%29+=+x\"
\n" ); document.write( "\"1%2B7x+-21+=+x\"
\n" ); document.write( "\"7x+-+20+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "Add +20 to each side:
\n" ); document.write( "\"7x+-20%2B+20+=+x%2B+20\"
\n" ); document.write( "\"7x=++x%2B20\"\r
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\n" ); document.write( "\n" ); document.write( "Now, subtract x from each side:
\n" ); document.write( "\"7x+-+x+=+x%2B20+-x\"
\n" ); document.write( "\"6x=+20\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by 6:\r
\n" ); document.write( "\n" ); document.write( "\"%286x%29%2Fx+=+20%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "Reduce the fraction:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+10%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Check to make sure no denominators are zero. The answer is acceptable.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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