document.write( "Question 168637: Find the perimeter of the equilateral traiangle inscribed in a circle of radius 20.0 inches \n" ); document.write( "
Algebra.Com's Answer #124399 by Mathtut(3670) ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "AC is equal to the radius 20. \n" ); document.write( "We know that angle C is half of the original angle of the original equilateral triangle(60) ....so C is 60/2=30. ABC is a right triangle so we know that angle A is a 60 degree angle 180-90-30=60 \n" ); document.write( ": \n" ); document.write( "BC is equal to 1/2 of the entire side of the equilateral triangle \r \n" ); document.write( "\n" ); document.write( "and we know that sine 60 degrees =BC/20(hypothenuse of the ABC)--->solving for BC=20(sine60degrees)=17.32 \n" ); document.write( ": \n" ); document.write( "now if we double BC we will have the entire length of one side of the equilateral triangle ( 17.32(2)=34.64)---> and since all sides are equal the Perimeter is three times this length. 34.64(3)=103.92 inches \n" ); document.write( " |