document.write( "Question 168739: the area of a square is 21 more than the perimeter. Find the length of a side \n" ); document.write( "
Algebra.Com's Answer #124384 by jim_thompson5910(35256)\"\" \"About 
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\"the area of a square is 21 more than the perimeter\" ----> \"A=P%2B21\"\r
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\n" ); document.write( "\n" ); document.write( "Remember, the area of a square is \"A=s%5E2\" and the perimeter of a square is \"P=4s\" where \"s\" is the side length\r
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\n" ); document.write( "\n" ); document.write( "So \"A=P%2B21\" becomes \"s%5E2=4s%2B21\"\r
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\n" ); document.write( "\n" ); document.write( "\"s%5E2-4s-21=0\" Subtract 4s from both sides. Subtract 21 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%28s-7%29%28s%2B3%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"s-7=0\" or \"s%2B3=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"s=7\" or \"s=-3\" Now solve for s in each case\r
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\n" ); document.write( "\n" ); document.write( "Now discard the solution \"s=-3\" since a negative side length does not make sense.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"s=7\" which means that the length of the side of the square is 7 units
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