document.write( "Question 23670: Hi, I am really having a hard time analyzing this one, I hope someone could help me on this and I would really really appreciate it so much.\r
\n" ); document.write( "\n" ); document.write( "Question 1 : Explain a sequence of steps that can be used to solve any quadratic equation in the QUICKEST WAY.\r
\n" ); document.write( "\n" ); document.write( "Question 2 : Derive the quadratic formula used in solving quadratic equations.
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Algebra.Com's Answer #12437 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
1) Determine whether or not the quadratic equation is factorable.
\n" ); document.write( "If it is factorable, then factor it and apply the zero product principle to find the roots.
\n" ); document.write( "If it is not factorable, or you are unable to determine its factorability, then use the quadratic formula to find the roots.\r
\n" ); document.write( "\n" ); document.write( "2) Derive the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "Start with the standard form of the general quadratic equation:
\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\" Divide through by a to get the x^2 coefficient = 1.
\n" ); document.write( "\"x%5E2+%2B+%28b%2Fa%29x+%2B+c%2Fa+=+0\" Subtract c/a form both sides of the equation.
\n" ); document.write( "\"x%5E2+%2B+%28b%2Fa%29x+=+-c%2Fa\" Complete the square in the x-terms by adding the square of half the x-coefficient to both sides.
\n" ); document.write( "\"x%5E2+%2B+%28b%2Fa%29x+%2B+%28b%5E2%2F4a%5E2%29+=+%28b%5E2%2F4a%5E2%29-c%2Fa\" Factor the left side.
\n" ); document.write( "\"%28x+%2B+b%2F2a%29%5E2+=+%28b%5E2%2F4a%5E2%29-c%2Fa\" Take the square root of both sides.
\n" ); document.write( "\"x+%2B+b%2F2a+=+sqrt%28%28b%5E2%2F4a%5E2%29-c%2Fa%29\" Note: There is (or should be) a + or - in front of the sqrt sign. Simplify the contents of the radical.
\n" ); document.write( "\"x+%2B+b%2F2a+=+sqrt%28%28b%5E2+-+4ac%29%2F4a%5E2%29\" Take the square root of the denominator on the right side.
\n" ); document.write( "\"x+%2B+b%2F2a+=+%28sqrt%28b%5E2+-+4ac%29%29%2F2a\" Subtract b/2a from both sides.
\n" ); document.write( "\"x+=+%28-b%2F2a%2B-sqrt%28b%5E2+-+4ac%29%2F2a%29\" Simplify the right side.
\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2+-+4ac%29%29%2F2a\" And there you have it!
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