document.write( "Question 168704: Given x-1(less then or equal to)3x + 1(less than or equal to) x + 5. Solve for x and show your answer on the number line and in interval notaion.
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Algebra.Com's Answer #124360 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x-1%3C=3x%2B1%3C=x%2B5\" Start with the given compound inequality.\r
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\n" ); document.write( "\n" ); document.write( "Break up the compound inequality to get:\r
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\n" ); document.write( "\n" ); document.write( "\"x-1%3C=3x%2B1\" AND \"3x%2B1%3C=x%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "So let's solve the first inequality \"x-1%3C=3x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-1%3C=3x%2B1\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=3x%2B1%2B1\" Add \"1\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x-3x%3C=1%2B1\" Subtract \"3x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%3C=1%2B1\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%3C=2\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=%282%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate \"x\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=-1\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve the second inequality \"3x%2B1%3C=x%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B1%3C=x%2B5\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%3C=x%2B5-1\" Subtract \"1\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-x%3C=5-1\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3C=5-1\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3C=4\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=%284%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\". \r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x%3E=-1\" and \"x%3C=2\".\r
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\n" ); document.write( "\n" ); document.write( "Our answer also looks like \"-1%3C=x%3C=2\".\r
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\n" ); document.write( "\n" ); document.write( "So the answer in interval notation is []\r
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\n" ); document.write( "\n" ); document.write( "Also, the answer in set-builder notation is \r
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\n" ); document.write( "\n" ); document.write( "Here's the graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( " Graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( "Note:\r
\n" ); document.write( "\n" ); document.write( "There is a closed circle at \"x=-1\" which means that we're including this value in the solution set\r
\n" ); document.write( "\n" ); document.write( "Also, there is a closed circle at \"x=2\" which means that we're including this value in the solution set.
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