document.write( "Question 23590: ax+by=c;y \n" ); document.write( "
Algebra.Com's Answer #12436 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
ax+by=c;y \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This means to take the equation ax +by = c, and solve for y.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To do this subtract ax from each side of the equation:
\n" ); document.write( "ax+by = c
\n" ); document.write( "ax-ax +by = c-ax\r
\n" ); document.write( "\n" ); document.write( "by = c-ax\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Next, since by means b TIMES y, you need to divide by b in order solve for y:
\n" ); document.write( "\"by+=+c-ax\"
\n" ); document.write( "\"%28by%29%2Fb+=+%28c-ax%29%2Fb\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28c-ax%29%2Fb\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( "
\n" );