document.write( "Question 23590: ax+by=c;y \n" ); document.write( "
Algebra.Com's Answer #12436 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! ax+by=c;y \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means to take the equation ax +by = c, and solve for y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To do this subtract ax from each side of the equation: \n" ); document.write( "ax+by = c \n" ); document.write( "ax-ax +by = c-ax\r \n" ); document.write( "\n" ); document.write( "by = c-ax\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next, since by means b TIMES y, you need to divide by b in order solve for y: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |