document.write( "Question 168709: (a). Evaluate 6^,5^0,4^0,3^0,2^0,and 1^0. If you are defining 0^0 what value would you give for 0^0?\r
\n" ); document.write( "\n" ); document.write( "0^0 is inderterminate expression. Based on your observation in in part (a) explain why you think 0^0 is indeterminate.
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Algebra.Com's Answer #124354 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
See this --> http://mathforum.org/dr.math/faq/faq.number.to.0power.html\r
\n" ); document.write( "\n" ); document.write( "x^0 where x is anything except 0 is defined as 1\r
\n" ); document.write( "\n" ); document.write( "You can see that \"x%5E0+=+x%5E%28y-y%29\"
\n" ); document.write( "\"x%5E%28y-y%29+=+%28x%5Ey%29%2F%28x%5Ey%29=+1\" for all x!=0
\n" ); document.write( "this works for all x except x=0. If x=0 then term (0^y) in the denominator is undefined
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