document.write( "Question 168683: The length of a rectangle is 8 in. more than twice its width. The perimeter of the rectangle of 70 in. Find the length and with of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #124330 by Earlsdon(6294) $\"\"$ $\"About$

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Let L = the length and W = the width.
\n" ); document.write( "The perimeter of a rectactangle is given by:
\n" ); document.write( " $\"P+=+2%28L%2BW%29\"$
\n" ); document.write( "From the problem, you have L = 2W+8 (The length is 8 in. more than twice its width). And P = 70 in. Substitute these for L and P in the formula.
\n" ); document.write( " $\"70+=+2%28%282W%2B8%29%2BW%29\"$ Simplify.
\n" ); document.write( " $\"70+=+2%283W%2B8%29\"$
\n" ); document.write( " $\"70+=+6W%2B16\"$ Subtract 16 from both sides.
\n" ); document.write( " $\"54+=+6W\"$ Divide both sides by 6.
\n" ); document.write( " $\"9+=+W\"$ and
\n" ); document.write( " $\"L+=+2W%2B8\"$
\n" ); document.write( " $\"L+=+2%289%29%2B8\"$
\n" ); document.write( " $\"L+=+18%2B8\"$
\n" ); document.write( " $\"L+=+26\"$
\n" ); document.write( "The length is 26 in. and the width is 9 in.
\n" ); document.write( "Check:
\n" ); document.write( " $\"P+=+2%28L%2BW%29\"$ Substitute L = 26 and W = 9
\n" ); document.write( " $\"P+=+2%2826%2B9%29\"$
\n" ); document.write( " $\"P+=+2%2835%29\"$
\n" ); document.write( " $\"P+=+70\"$ It checks! \n" ); document.write( "

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