document.write( "Question 168666: Each month in UP. a year level generates an average of 28 lbs of paper trash for recycling. Assume the standard deviation is 21lbs. Assume the variable is approximately normally distributed. If a year level is selected at random find the percentage of generating:
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document.write( "A. 0 between 27 and 31 lbs per month.
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document.write( "B. More than 30.2 lbs per month. \n" );
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Algebra.Com's Answer #124321 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Each month in UP. a year level generates an average of 28 lbs of paper trash for recycling. Assume the standard deviation is 21lbs. Assume the variable is approximately normally distributed. If a year level is selected at random find the percentage of generating: \n" ); document.write( "A. 0 between 27 and 31 lbs per month. \n" ); document.write( "z(27) = (27-28)/21 = -0.04762 \n" ); document.write( "z(31) = (31-28)/21 = 0.14286 \n" ); document.write( "P(27 < x < 31) = P(-0.04762 < z < 0.14286) = 0.07579 \n" ); document.write( "--------------------------------------- \n" ); document.write( "B. More than 30.2 lbs per month. \n" ); document.write( "z(30.2) = (30.2-28)/21 = 0.104762 \n" ); document.write( "P(x > 30.2) = P(z > 0.104762) = 0.45828.. \n" ); document.write( "========================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |