document.write( "Question 168674: A motorcycle breaks down and the rider must walk the rest of the way to work. The motorcycle was being driven at 45mph, and the rider walks at a speed of 6 mph. The distance from home to work is 25 miles, and the total for the trip was 2 hours. How far did the motorcycle go before it broke down? \n" ); document.write( "
Algebra.Com's Answer #124319 by stanbon(75887)\"\" \"About 
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A motorcycle breaks down and the rider must walk the rest of the way to work. The motorcycle was being driven at 45mph, and the rider walks at a speed of 6 mph. The distance from home to work is 25 miles, and the total for the trip was 2 hours. How far did the motorcycle go before it broke down?
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\n" ); document.write( "Motorcycle DATA:
\n" ); document.write( "rate = 45 mph ; distance = x miles; time = x/45 hrs.
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\n" ); document.write( "Walking DATA:
\n" ); document.write( "rate = 6 mph ; distance = 25-x miles ; time = (25-x)/6 hrs.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time + time = 2 hrs
\n" ); document.write( "x/45 + (25-x)/6 = 2
\n" ); document.write( "6x + 45(25-x) = 2*6*45
\n" ); document.write( "6x + 25*45 - 45x = 12*45
\n" ); document.write( "-39x = -13*45
\n" ); document.write( "x = 15 miles (distance the motorcycle went)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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