document.write( "Question 168536: 2ax-2bx+ay-by \n" ); document.write( "
Algebra.Com's Answer #124318 by midwood_trail(310)\"\" \"About 
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2ax-2bx+ay-by\r
\n" ); document.write( "\n" ); document.write( "I assume you want to factor.\r
\n" ); document.write( "\n" ); document.write( "When you have 4 terms, it is best to factor by groups.\r
\n" ); document.write( "\n" ); document.write( "2ax - 2bx = group 1\r
\n" ); document.write( "\n" ); document.write( "ay - by = group 2\r
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\n" ); document.write( "\n" ); document.write( "2ax - 2bx = 2x( a - b)\r
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\n" ); document.write( "\n" ); document.write( "ay - by = y(a - b)\r
\n" ); document.write( "\n" ); document.write( "Do you see the quantity (a - b)?\r
\n" ); document.write( "\n" ); document.write( "We only need one of them.\r
\n" ); document.write( "\n" ); document.write( "Final answer: (2x + y)(a - b)\r
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