document.write( "Question 168594: 2ab+2ay+bx+xy \n" ); document.write( "

Algebra.Com's Answer #124315 by midwood_trail(310) $\"\"$ $\"About$

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Yu did not state directions but I assume you want to factor, right?\r
\n" ); document.write( "\n" ); document.write( "2ab + 2ay + bx + xy\r
\n" ); document.write( "\n" ); document.write( "When you have 4 terms, it is best to factor by groups.\r
\n" ); document.write( "\n" ); document.write( "2ab + 2ay = group 1\r
\n" ); document.write( "\n" ); document.write( "bx + xy = group 2\r
\n" ); document.write( "\n" ); document.write( "Factor each group individually.\r
\n" ); document.write( "\n" ); document.write( "2ab + 2ay = 2a(b + y)\r
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\n" ); document.write( "\n" ); document.write( "bx + xy = x(b + y)\r
\n" ); document.write( "\n" ); document.write( "We now have this:\r
\n" ); document.write( "\n" ); document.write( "2a(b + y)x(b + y)\r
\n" ); document.write( "\n" ); document.write( "Notice that we have two quantities that are the same, which is (b + y).\r
\n" ); document.write( "\n" ); document.write( "We only need one of them.\r
\n" ); document.write( "\n" ); document.write( "Your final answer is the following two factors:\r
\n" ); document.write( "\n" ); document.write( "(2a + x)(b + y)\r
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