document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168668>Question 168668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x-1/2x=40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124304 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3x-1)/2x = 40\r<BR>\n" );
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document.write( "We first multiply both sides by 2x to remove the fraction on the left side.<BR>\n" );
document.write( "Here, 2x represents the LCD.\r<BR>\n" );
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document.write( "(3x-1)/2x times 2x = 3x - 1\r<BR>\n" );
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document.write( "40 times 2x = 80x\r<BR>\n" );
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document.write( "We now have a linear equation:\r<BR>\n" );
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document.write( "3x - 1 = 80x\r<BR>\n" );
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document.write( "Solve for x.\r<BR>\n" );
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document.write( "-1 = 80x - 3x\r<BR>\n" );
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document.write( "-1 = 77x\r<BR>\n" );
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document.write( "Divide both sides by 77 to find x.\r<BR>\n" );
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document.write( "-1/77 = x\r<BR>\n" );
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document.write( "I hope this helps. </SPAN>\n" );
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