document.write( "Question 168625: Find a six-digit number in which the first digit is two less than the second.\r
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document.write( "The second digit is two less than the third.\r
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document.write( "The third digit is two less than the fourth.\r
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document.write( "And the fourth digit is two less than the fifth.\r
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document.write( "The first and last digits are the same.\r
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document.write( "Please show the work, i would appreciate it! \n" );
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Algebra.Com's Answer #124297 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! lets call the six digits consecutively A,B,C,D,E,F....these must all be single digits\r \n" ); document.write( "\n" ); document.write( "A=B-2 \n" ); document.write( "B=C-2 \n" ); document.write( "C=D-2 \n" ); document.write( "D=E-2 \n" ); document.write( "E=unknown \n" ); document.write( "F=A\r \n" ); document.write( "\n" ); document.write( "now plug in B,C,D values(one at a time), into 1st equation and you arrive at\r \n" ); document.write( "\n" ); document.write( "A=E-8\r \n" ); document.write( "\n" ); document.write( "now in order for A to be a single digit number E-8>0 or E>8 since 9 is the only single digit remaining above 8 then E=9\r \n" ); document.write( "\n" ); document.write( "since E=9 it follows that D=7,C=5,B=3, and A=1, and since A=F F=1 also\r \n" ); document.write( "\n" ); document.write( "so we have 1,3,5,7,9,1 as the six digit number. \n" ); document.write( ": \n" ); document.write( "I got to thinking that 0 is also a digit so the above E-8>0 should really be \n" ); document.write( "\n" ); document.write( "so E can be 8 or 9 ...we already have the answer if E is 9..If E is 8\r \n" ); document.write( "\n" ); document.write( "it would be 0,2,4,6,8,0\r \n" ); document.write( "\n" ); document.write( "so two possibilities in my opinion because I see nothing that narrows it down to one or the other. \n" ); document.write( " |