document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23643>Question 23643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me find  out how to do this problem! \r<BR>\n" );
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document.write( "If   g(x)=x^2-4x+1 find the value if:     -2g(3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12428 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given g(x)=x^2-4x+1 , then to find g(3), just substitute the 3 in place of all the x's:<BR>\n" );
document.write( "g(3) = (3)^2 -4*(3)+1<BR>\n" );
document.write( "g(3) = 9-12 +1 = -2\r<BR>\n" );
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document.write( "Now, -2g(3) means to take the value of g(3) and multiply times -2.\r<BR>\n" );
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document.write( "-2g(3) = -2*(-2)= 4\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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