document.write( "Question 168604: Kathy has 5 liters of a 32% acid solution and she4 also has a large amount of a 26% acid solution. How many liters of the 26% solution can Kathy mix with the 5 liters of 32% solution in order to produce a 50% acid solution?\r
\n" ); document.write( "\n" ); document.write( "the answer isn't possible in the end but i need to know the values of x and y and write out a system of equations from the information given and then solve hte system of equations using substitution or elimination \n" ); document.write( "

Algebra.Com's Answer #124261 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Kathy has 5 liters of a 32% acid solution and she also has a large amount of a
\n" ); document.write( " 26% acid solution. How many liters of the 26% solution can Kathy mix with
\n" ); document.write( "the 5 liters of 32% solution in order to produce a 50% acid solution?
\n" ); document.write( ":
\n" ); document.write( "I think you would just use a typical mixture equation, if it's impossible, it
\n" ); document.write( " will let you know, by giving a negative solution.
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\n" ); document.write( "Let x = amt of 26% solution (why would you need y?)
\n" ); document.write( ":
\n" ); document.write( ".32(5) + .26x = .50(x+5)
\n" ); document.write( ":
\n" ); document.write( "1.6 + .26x = .50x = 2.5
\n" ); document.write( ":
\n" ); document.write( ".26x - .50x = 2.5 - 1.6
\n" ); document.write( "-.24x = .9
\n" ); document.write( "x = $\".9%2F%28-.24%29\"$
\n" ); document.write( "x = -3.75; clearly, not of the real world
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\n" ); document.write( "Substitution will show the equation is satisfied, but negative substances don't exist \n" ); document.write( "

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