document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168568>Question 168568</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> a three-digit number, which is divisible by 10, has a hundreds digit that is ove less than its tens digit. the number also is 52 times the sum of its digits. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124248 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a three-digit number, which is divisible by 10, has a hundreds digit that is ove less than its tens digit. the number also is 52 times the sum of its digits. find the number<BR>\n" );
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document.write( "Since it is divisible by 10 let the number be 100a + 10b <BR>\n" );
document.write( "a = b - 1<BR>\n" );
document.write( "100a + 10b = 52(a+b) <BR>\n" );
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document.write( "Use substitution to bolve for \"b\".<BR>\n" );
document.write( "100(b-1) + 10b = 52(b-1+b)<BR>\n" );
document.write( "100b - 100 + 10b = 104b - 52<BR>\n" );
document.write( "6b = 48<BR>\n" );
document.write( "b = 8<BR>\n" );
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document.write( "solve for \"a\":<BR>\n" );
document.write( "a = 8-1 = 7<BR>\n" );
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document.write( "The number is 100*7 + 8*10 = 780<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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