document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168547>Question 168547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a couple of homework problems that I am having trouble with.  Any help you can give me to understand how to work these problems would be appreciated.  \r<BR>\n" );
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document.write( "The Cotes have 30 feet of picket fence with which to enclose a flower garden.  What dimensions should the garden have in order to maximaze area?  I believe the equation I would use is A(w) = (30-2)w.\r<BR>\n" );
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document.write( "Find the value of \"a\" such that f(x)=ax2+16x+38 has a minimum value of 6.  Would this answer be 96/19?\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124214 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have a couple of homework problems that I am having trouble with. Any help you can give me to understand how to work these problems would be appreciated. <BR>\n" );
document.write( "The Cotes have 30 feet of picket fence with which to enclose a flower garden. What dimensions should the garden have in order to maximaze area? I believe the equation I would use is A(w) = (30-2)w. <BR>\n" );
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document.write( "30 feet is the perimeter of the enclosed area.  The max area is a circle for a given perimeter.  You didn't specify the shape.  If it's to be a rectangle, the max area is a square.<BR>\n" );
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document.write( "Find the value of \"a\" such that f(x)=ax2+16x+38 has a minimum value of 6. Would this answer be 96/19?<BR>\n" );
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document.write( "The minimum is the point where the 1st derivative is 0, so<BR>\n" );
document.write( "2ax + 16 = 0<BR>\n" );
document.write( "x = -8/a at the minimum.<BR>\n" );
document.write( "Subbing -8/a for x and setting = 6:<BR>\n" );
document.write( "a*(64/a^2) - 128/a + 38 = 6<BR>\n" );
document.write( "64 - 128 + 38a = 6a<BR>\n" );
document.write( "a = 2<BR>\n" );
document.write( "Email me if you have questions, this is a complex problem.  gsihoutx@aol.com\r<BR>\n" );
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