document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23688>Question 23688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem is:(3y/x^4)^-3... I can not figure out how they came up with the answer of x^12/27y^3... I keep coming up with the invert of this answer... I just can't figure out how they got it to a positive and inverted it. Thanks for you help.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12421 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I guess you didn't give the whole problem, so I'll assume there is more to this.  However, remember that if you have a fraction raised to the -1 power, it means the reciprocal of the fraction, which means to invert the fraction.\r<BR>\n" );
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document.write( "For example, if you had <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28a%2Fb%29%5E%28-1%29 ALIGN=MIDDLE  ALT=\"%28a%2Fb%29%5E%28-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > this actually means <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%2Fa ALIGN=MIDDLE  ALT=\"b%2Fa\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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