document.write( "Question 168522: I've checked all over this site, but can't find a response for these 2 problems.
\n" ); document.write( "Please help!\r
\n" ); document.write( "\n" ); document.write( "1.Find the coordinates of the point C, halfway between the points A(5,1) and B(-2,7).\r
\n" ); document.write( "\n" ); document.write( "2. What is the equation of the perpendicular bisector of teh line between the points (2,2) and (6,6)?\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance for any help!
\n" ); document.write( "Andrew
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Algebra.Com's Answer #124198 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
I've checked all over this site, but can't find a response for these 2 problems.
\n" ); document.write( "Please help!
\n" ); document.write( "1.Find the coordinates of the point C, halfway between the points A(5,1) and B(-2,7).
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\n" ); document.write( "The easiest way to do these is to find the average of x and y separately.
\n" ); document.write( "A(5,1) and B(-2,7).
\n" ); document.write( "For x: (5 + (-2))/2 = 3/2
\n" ); document.write( "For y: (1+7)/2 = 4
\n" ); document.write( "So the point is (3/2,4) or (1.5,4)
\n" ); document.write( "-------------------------\r
\n" ); document.write( "\n" ); document.write( "2. What is the equation of the perpendicular bisector of teh line between the points (2,2) and (6,6)?
\n" ); document.write( "The mid-point is found in the same way as above, and is (4,4).
\n" ); document.write( "The slope of the line is the (diff in y)/(diff in x) = 1
\n" ); document.write( "The slope, m, of a line perpendicular is the negative inverse, = -1.
\n" ); document.write( "Then,
\n" ); document.write( "y-y1 = m*(x-x1) where (x1,y1) is the point (4,4)
\n" ); document.write( "y-4 = -1(x-4)
\n" ); document.write( "y-4 = -x + 4
\n" ); document.write( "x+y = 8\r
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