document.write( "Question 168430: I am trying to solve y=x2-6x. so far column x is 0 1 2 3 4 column y is 0 -5 -8 a=1 b=-6 c=0. At school I understood where to get these #s now im lost. not sure how i need to do this \n" ); document.write( "
Algebra.Com's Answer #124184 by KnightOwlTutor(293)\"\" \"About 
You can put this solution on YOUR website!
This is a quadratic equation ax^2+bx+c=0\r
\n" ); document.write( "\n" ); document.write( "In your equation a=1 b=-6 and c=0\r
\n" ); document.write( "\n" ); document.write( "The y column is the value of y at the indicated x value.\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-6x%2B0+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-6%29%5E2-4%2A1%2A0=36\".
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\n" ); document.write( " Discriminant d=36 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--6%2B-sqrt%28+36+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-6%29%2Bsqrt%28+36+%29%29%2F2%5C1+=+6\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-6%29-sqrt%28+36+%29%29%2F2%5C1+=+0\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-6x%2B0\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-6x%2B0+=+1%28x-6%29%2A%28x-0%29\"
\n" ); document.write( " Again, the answer is: 6, 0.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-6%2Ax%2B0+%29\"
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