document.write( "Question 23672: (2u^3-13u^2-8u+7)divided by (u-7)
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document.write( "I have the quotient as 2u^2+u-15 with a
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document.write( "remainder of 105
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document.write( " Useing long division
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document.write( "This seems wrong because the reamainder
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document.write( "was 0-105. Please help me out.
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document.write( "Thank you \n" );
document.write( "
Algebra.Com's Answer #12417 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! (2u^3-13u^2-8u+7)divided by (u-7)...YOU CAN USE SHORT DIVISION FOR THIS ... \n" ); document.write( "LET U-7=0...U=7\r \n" ); document.write( "\n" ); document.write( "7....|.......2........-13.......-8..........7 \n" ); document.write( ".....|.......0........14........7..........-7 \n" ); document.write( "------------------------------------------------- \n" ); document.write( ".....|.......2.........1.........-1.........0 \n" ); document.write( "HENCE REMINDER IS ZERO \n" ); document.write( "QUOTIENT IS 2U^2+U-1.... \n" ); document.write( "IF YOU SHOW YOUR WORKING , WE CAN TELL WHERE YOU HAVE ERRED. \n" ); document.write( " \n" ); document.write( " |