document.write( "Question 168436This question is from textbook beginning and intermeidate alegebra 4th edition
\n" ); document.write( ": the width of a rectangle is 3ft less than the length. The perimerter is 62ft. Find the length and the width of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #124158 by midwood_trail(310) $\"\"$ $\"About$

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The width of a rectangle is 3ft less than the length. The perimerter is 62ft. Find the length and the width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "width = x - 3\r
\n" ); document.write( "\n" ); document.write( "length = x\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 62\r
\n" ); document.write( "\n" ); document.write( "62 = 2x + 2(x - 3)\r
\n" ); document.write( "\n" ); document.write( "62 = 2x + 2x - 6\r
\n" ); document.write( "\n" ); document.write( "62 = 4x - 6\r
\n" ); document.write( "\n" ); document.write( "62 + 6 = 4x\r
\n" ); document.write( "\n" ); document.write( "68 = 4x\r
\n" ); document.write( "\n" ); document.write( "68/4 = x\r
\n" ); document.write( "\n" ); document.write( "17 = x\r
\n" ); document.write( "\n" ); document.write( "The length is 17 feet.\r
\n" ); document.write( "\n" ); document.write( "The width is 3 less than 17 or 14 feet.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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