document.write( "Question 168365: the length of a certain rectangle is 4 cm longer than its width. if the width were increased by 6cm and the length were doubled, the new perimter would be twice the perimter of the original rectangle. find the dimensions of the orginal rectangle.\r
\n" ); document.write( "\n" ); document.write( "please send me the formula so i can figure it out\r
\n" ); document.write( "\n" ); document.write( "thank you \n" ); document.write( "
Algebra.Com's Answer #124128 by ankor@dixie-net.com(22740)\"\" \"About 
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he length of a certain rectangle is 4 cm longer than its width. if the width were increased by 6cm and the length were doubled, the new perimter would be twice the perimter of the original rectangle. find the dimensions of the orginal rectangle.
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\n" ); document.write( "Let x = the width of the original rectangle
\n" ); document.write( "Then
\n" ); document.write( "(x+4) = the length of the original rectangle
\n" ); document.write( "and
\n" ); document.write( "(x+6) = width of new rectangle
\n" ); document.write( "and
\n" ); document.write( "2(x+4) = length of new rectangle
\n" ); document.write( ":
\n" ); document.write( "New perimeter = twice old perimeter
\n" ); document.write( "2(2(x+4) + 2(x+6) = 2(2(x+4) + 2x)
\n" ); document.write( "4x + 16 + 2x + 12 = 4x + 16 + 4x
\n" ); document.write( "6x + 28 = 8x + 16
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