document.write( "Question 168386: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( " A rectangular pond measures 3m by 5m. A concrete walk of uniform width is constructed around the pond. If the walk and pond together cover an area of 39m^2, how wide is the walk?
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Algebra.Com's Answer #124117 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
3*5=15 M^2 FOR THE POND.
\n" ); document.write( "(3+2X)(5+2X)=39
\n" ); document.write( "15+10X+6X+4X^2-39=0
\n" ); document.write( "4X^2+16X-24=0
\n" ); document.write( "4(X^2+4X-6)=0
\n" ); document.write( "USING THE QUADRATIC EQUATION\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"WE GET:
\n" ); document.write( "X=(-4+-SQRT[4^2-4*1*-6])/2*1
\n" ); document.write( "X=(-4+-SQRT16+24])/2
\n" ); document.write( "X=(-4+-SQRT40)/2
\n" ); document.write( "X=(-4+-6.325)/2
\n" ); document.write( "X=(-4+6.32)/2
\n" ); document.write( "X=2.32/2
\n" ); document.write( "X=1.16 M. IS THE WIDTH OF THE WALK.
\n" ); document.write( "PROOF:
\n" ); document.write( "(3+2*1.16)(5+2*1.16)=39
\n" ); document.write( "(3*2.32)(5+2.32)=39
\n" ); document.write( "5.32*7.32=39
\n" ); document.write( "39~39 \r
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