document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168387>Question 168387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem:\r<BR>\n" );
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document.write( "    A rectangular counter is covered with 600 square tiles. The counter could have been covered with 400 tiles 1cm longer on a side. Fing the length of a side of the smaller tile. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124114 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular counter is covered with 600 square tiles. <BR>\n" );
document.write( "So the area of the counter is 600x^2 where x is the length of a side of a tile.<BR>\n" );
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document.write( "The counter could have been covered with 400 tiles 1cm longer on a side. <BR>\n" );
document.write( "So the area of the counter is 400(x+1)^2<BR>\n" );
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document.write( "Find the length of a side of the smaller tile.<BR>\n" );
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document.write( "Area 1st = Area 2nd<BR>\n" );
document.write( "600x^2 = 400(x+1)^2<BR>\n" );
document.write( "600x^2 = 400(x^2+2x+1)<BR>\n" );
document.write( "600x^2 = 400x^2 + 800x + 400<BR>\n" );
document.write( "200x^2 - 800x - 400 = 0<BR>\n" );
document.write( "x^2 - 4x - 2 = 0<BR>\n" );
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document.write( "x = [4 +- sqrt(16 - 4*-2)]/2\r<BR>\n" );
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document.write( "x = [4 +- sqrt(24)]/2\r<BR>\n" );
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document.write( "x = [4 +- 2sqrt(6)]/2\r<BR>\n" );
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document.write( "Positive solution:\r<BR>\n" );
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document.write( "x = 2 + 2sqrt(6) cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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