document.write( "Question 168385: I need to determine x, y and z when x+y+z=1150 and x=4z-100 and x=6y+50. So far the only thing I have figured out is that 1150=1150. Not a good answer. \r
\n" ); document.write( "\n" ); document.write( "Can someone please help.
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Algebra.Com's Answer #124112 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
determine x, y and z when
\n" ); document.write( "x+y+z=1150
\n" ); document.write( "x=4z-100
\n" ); document.write( "x=6y+50
\n" ); document.write( "-------------
\n" ); document.write( "x + y + z = 1150
\n" ); document.write( "x + 0 -4z = -100
\n" ); document.write( "x -6y + 0 = 50
\n" ); document.write( "--------------------
\n" ); document.write( "Use any method to solve the system to get:
\n" ); document.write( "x = 800
\n" ); document.write( "y = 125
\n" ); document.write( "z = 225
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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