document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168379>Question 168379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is three times as long as it is wide. If the length and the width are each increased by 4, the area is increased by 176. Find the dimensions of the orginial rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124103 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124103\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W<BR>\n" );
document.write( "3W*W=(L+4)(W+4)-176<BR>\n" );
document.write( "3W^2=(3W+4)(W+4)-176<BR>\n" );
document.write( "3W^2=3W^2+12W+4W+16-176<BR>\n" );
document.write( "0=16W+16-176<BR>\n" );
document.write( "16W=-16+176<BR>\n" );
document.write( "16W=160<BR>\n" );
document.write( "W=160/16<BR>\n" );
document.write( "W=10 ANS. FOR THE ORIGINAL WIDTH .<BR>\n" );
document.write( "L=3*10=30 ANS. FOR THE ORIGINAL LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "10*30=(10+4)(30+4)-176<BR>\n" );
document.write( "300=14*34-176<BR>\n" );
document.write( "300=476-176<BR>\n" );
document.write( "300=300<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );