document.write( "Question 168375: Please help me solve this problem:\r
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document.write( " A square picture is mounted in a frame 1 cm wide. The area of the picture is 2/3 of the total area. Find the lenght of a side of the picture. \r
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document.write( "thank you \n" );
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Algebra.Com's Answer #124100 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! x^2=2/3(x+2)^2 \n" ); document.write( "x^2=2/3(x^2+4x+4) \n" ); document.write( "x^2=(2x^2+8x+8)/3 \n" ); document.write( "3x^2=2x^2+8x+8 \n" ); document.write( "3x^2-2x^2-8x-8=0 \n" ); document.write( "x^2-8x-8=0 \n" ); document.write( "using the quadratic eqation \n" ); document.write( "x=(8+-sqrt[-8^2-4*1*-8])/2*1 \n" ); document.write( "x=(8+-sqrt[64+32]) /2 \n" ); document.write( "x=(8+-sqrt96)/2 \n" ); document.write( "x=(8+-9.7979589)/2 \n" ); document.write( "x=(8+9.7979589)/2 \n" ); document.write( "x=17.7979589/2 \n" ); document.write( "x=8.898979 ans. for the length of the side of the picture. \n" ); document.write( "Proof: \n" ); document.write( "8.898979^2=2/3(10.898979)^2 \n" ); document.write( "79.19182=2/3*118.78774 \n" ); document.write( "79.19182=79.19182 \n" ); document.write( " |