document.write( "Question 168295: The width of a rectangle is 12 units less than the length. The perimeter is 108 units. Find the length. \n" ); document.write( "
Algebra.Com's Answer #124073 by checkley77(12844)\"\" \"About 
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W=L-12
\n" ); document.write( "2W+2L=108
\n" ); document.write( "2(L-12)+2L=108
\n" ); document.write( "2L-24+2L=108
\n" ); document.write( "4L=108+24
\n" ); document.write( "4L=132
\n" ); document.write( "L=132/4
\n" ); document.write( "L=33 IS THE LENGTH.
\n" ); document.write( "W=33-12
\n" ); document.write( "W=21 IS THE LENGTH.
\n" ); document.write( "pROOF:
\n" ); document.write( "2*21+2*33=108
\n" ); document.write( "42+66=108
\n" ); document.write( "108=108
\n" ); document.write( "
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