document.write( "Question 168295: The width of a rectangle is 12 units less than the length. The perimeter is 108 units. Find the length. \n" ); document.write( "
Algebra.Com's Answer #124073 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! W=L-12 \n" ); document.write( "2W+2L=108 \n" ); document.write( "2(L-12)+2L=108 \n" ); document.write( "2L-24+2L=108 \n" ); document.write( "4L=108+24 \n" ); document.write( "4L=132 \n" ); document.write( "L=132/4 \n" ); document.write( "L=33 IS THE LENGTH. \n" ); document.write( "W=33-12 \n" ); document.write( "W=21 IS THE LENGTH. \n" ); document.write( "pROOF: \n" ); document.write( "2*21+2*33=108 \n" ); document.write( "42+66=108 \n" ); document.write( "108=108 \n" ); document.write( " |