document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23678>Question 23678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cards are drawn at random from a standard deck of cards.  What is the probability that both cards are aces? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12407 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm assuming that you are NOT replacing the first card and then drawing the second.  For the first card drawn , probability of ace is 4/52.  Then for the second card, after the first ace is drawn, there are only 3 aces left out of 51 cards, so probability is 3/51.  The probability of performing two independent activities such as this is actually the product of the probabilities:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%2F52%29%2A%283%2F51%29 ALIGN=MIDDLE  ALT=\"%284%2F52%29%2A%283%2F51%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This reduces to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F13%29%2A%281%2F17%29+=+1%2F221 ALIGN=MIDDLE  ALT=\"%281%2F13%29%2A%281%2F17%29+=+1%2F221\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "R^2 at SCC  </SPAN>\n" );
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