document.write( "Question 168325This question is from textbook
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document.write( ": xy-3x+4y-12/ xy+5x+4y+20
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document.write( "xy+6x-3y-18 xy+5x-3y-15\r
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document.write( "i know i have to flip it ,but not quite sure where to go from there \n" );
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Algebra.Com's Answer #124059 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! xy-3x+4y-12/ xy+5x+4y+20\r \n" ); document.write( "\n" ); document.write( "[x(y-3) + 4(y-3)] / [x(y+5) + 4(y+5)]\r \n" ); document.write( "\n" ); document.write( "[(x+4)(y-3)] / [(x+4)(y+5)]\r \n" ); document.write( "\n" ); document.write( "Cancel the common x+4 factor to get:\r \n" ); document.write( "\n" ); document.write( "= (y-3)/(y+5)\r \n" ); document.write( "\n" ); document.write( "=======================\r \n" ); document.write( "\n" ); document.write( "xy+6x-3y-18/ xy+5x-3y-15 \r \n" ); document.write( "\n" ); document.write( "[x(y+6) -3(y+6)] / [x(y+5) -3(y+5)]\r \n" ); document.write( "\n" ); document.write( "[(x-3)(y+6)] / [(x-3)(y+5)]\r \n" ); document.write( "\n" ); document.write( "= (y+6)/(y+5)\r \n" ); document.write( "\n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |