document.write( "Question 168278This question is from textbook Introductory Algebra
\n" ); document.write( ": (3a-5)/(a^2+4a+3)+(2a+2)/(a+3)=(a-3)/(a+1)\r
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Algebra.Com's Answer #124052 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"%28%283a-5%29%29%2F%28%28a%5E2%2B4a%2B3%29%29\" + \"%28%282a%2B2%29%29%2F%28%28a%2B3%29%29\" = \"%28%28a-3%29%29%2F%28%28a%2B1%29%29\"
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\n" ); document.write( "Factor where we can:
\n" ); document.write( "\"%28%283a-5%29%29%2F%28%28a%2B3%29%28a%2B1%29%29\" + \"%282%28a%2B1%29%29%2F%28%28a%2B3%29%29\" = \"%28%28a-3%29%29%2F%28%28a%2B1%29%29\"
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\n" ); document.write( "Multiply equation by (a+3)(x+1)
\n" ); document.write( "(a+3)(a+1)*\"%28%283a-5%29%29%2F%28%28a%2B3%29%28a%2B1%29%29\" + (a+3)(a+1)*\"%282%28a%2B1%29%29%2F%28%28a%2B3%29%29\" = (a+3)(a+1)*\"%28%28a-3%29%29%2F%28%28a%2B1%29%29\"
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\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "(3a-5) + 2(a+1)(a+1) = (a+3)(a-3)
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\n" ); document.write( "FOIL
\n" ); document.write( "(3a - 5) + 2(a^2 + 2a + 1) = a^2 - 9
\n" ); document.write( ":
\n" ); document.write( "3a - 5 + 2a^2 + 4a + 2 = a^2 - 9
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\n" ); document.write( "Combine like terms on the left:
\n" ); document.write( "2a^2 - a^2 + 3a + 4a - 5 + 2 + 9 = 0
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\n" ); document.write( "a^2 + 7a + 6 = 0
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\n" ); document.write( "Factor this to:
\n" ); document.write( "(a + 6)(a + 1) = 0
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\n" ); document.write( "a = -6
\n" ); document.write( "and
\n" ); document.write( "a = -1
\n" ); document.write( ":
\n" ); document.write( "Check solution of x=-6 in original equation
\n" ); document.write( "\"%28%283%28-6%29-5%29%29%2F%28%28-6%5E2%2B4%28-6%29%2B3%29%29\" + \"%28%282%28-6%29%2B2%29%29%2F%28%28-6%2B3%29%29\" = \"%28%28-6-3%29%29%2F%28%28-6%2B1%29%29\"
\n" ); document.write( "Do the math, find the common denominator, and you have;
\n" ); document.write( "\"-23%2F15\" + \"50%2F15\" = \"27%2F15\"
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\n" ); document.write( " x=-1 can not be a solution, note that in the last denominator we have division by 0
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