document.write( "Question 168278This question is from textbook Introductory Algebra
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document.write( ": (3a-5)/(a^2+4a+3)+(2a+2)/(a+3)=(a-3)/(a+1)\r
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Algebra.Com's Answer #124052 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ": \n" ); document.write( "Factor where we can: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by (a+3)(x+1) \n" ); document.write( "(a+3)(a+1)* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators and you have: \n" ); document.write( "(3a-5) + 2(a+1)(a+1) = (a+3)(a-3) \n" ); document.write( ": \n" ); document.write( "FOIL \n" ); document.write( "(3a - 5) + 2(a^2 + 2a + 1) = a^2 - 9 \n" ); document.write( ": \n" ); document.write( "3a - 5 + 2a^2 + 4a + 2 = a^2 - 9 \n" ); document.write( ": \n" ); document.write( "Combine like terms on the left: \n" ); document.write( "2a^2 - a^2 + 3a + 4a - 5 + 2 + 9 = 0 \n" ); document.write( ": \n" ); document.write( "a^2 + 7a + 6 = 0 \n" ); document.write( ": \n" ); document.write( "Factor this to: \n" ); document.write( "(a + 6)(a + 1) = 0 \n" ); document.write( ": \n" ); document.write( "a = -6 \n" ); document.write( "and \n" ); document.write( "a = -1 \n" ); document.write( ": \n" ); document.write( "Check solution of x=-6 in original equation \n" ); document.write( " \n" ); document.write( "Do the math, find the common denominator, and you have; \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " x=-1 can not be a solution, note that in the last denominator we have division by 0 \n" ); document.write( " |