document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168283>Question 168283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem!  Find the number of the sides of a regular polygon if each exterior angle measure is 18??  I'm stumped.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124036 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem! Find the number of the sides of a regular polygon if each exterior angle measure is 18?? I'm stumped. <BR>\n" );
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document.write( "The sum of the INTERIOR angle of a polygon with n sides is 180*(n-2).  Each angle is (180*(n-2))/n.  <BR>\n" );
document.write( "The exterior angles are 180-interior angle, so this is a polygon with interior angles of 162 degrees.<BR>\n" );
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document.write( "So, 180*(n-2)/n = 162<BR>\n" );
document.write( "180*(n-2) = 162n<BR>\n" );
document.write( "180n-360 = 162n<BR>\n" );
document.write( "18n = 360<BR>\n" );
document.write( "n = 20<BR>\n" );
document.write( "I don't remember the name of that one, maybe duodecagon. </SPAN>\n" );
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