document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168256>Question 168256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem: \r<BR>\n" );
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document.write( "There is only one positive integer which is exactly twice the sum of its digits.  Find this two digit number and show how you got your work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124027 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trial and error sounds good (with a bit of extra thinking on the side)<BR>\n" );
document.write( "If the number is twice the sum of its digits then the number must be even. Lets try 12.<BR>\n" );
document.write( "12. 1 + 2 = 3 but 12 is not twice 3.<BR>\n" );
document.write( "Using that idea the numbers have to total at least 7 so double 7 would be 14.<BR>\n" );
document.write( "The two digit number with digits totalling 7 would be 16. <BR>\n" );
document.write( "16. 1 + 6 = 7 but 16 is not twice 7 but we are getting closer (next even number to try is 18)<BR>\n" );
document.write( "18. 1 + 8 = 9 and 18 is twice 9<BR>\n" );
document.write( "So the number is 18. </SPAN>\n" );
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