document.write( "Question 2732: I am studing the substitution Method.. and for some reason i can not seem to figure out how to do it. My teacher has been trying to work with me, but yet when I look at the problem I go blank on what to do.
\n" ); document.write( "I have an equation y = 2x + 7
\n" ); document.write( " y = 10x - 1 I dont understand how to do this...
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #1240 by xcentaur(357) $\"\"$ $\"About$

You can put this solution on YOUR website!
y = 2x + 7 .... [1]
\n" ); document.write( "y = 10x - 1 .... [2]
\n" ); document.write( "

\n" ); document.write( "y=2x+7
\n" ); document.write( "2x=y-7
\n" ); document.write( "x=(y-7)/2 ...... [3]
\n" ); document.write( "

\n" ); document.write( "Substituting value of [3] in [2],
\n" ); document.write( "y=10x-1
\n" ); document.write( "y=(10(y-7)/2)-1
\n" ); document.write( "y=5(y-7)-1
\n" ); document.write( "y=5y-35-1
\n" ); document.write( "y-5y=-35-1
\n" ); document.write( "-4y=-36
\n" ); document.write( "y=-36/-4
\n" ); document.write( "y=9
\n" ); document.write( "

\n" ); document.write( "Also,putting y=9 in equation [1] we get,
\n" ); document.write( "y=2x+7
\n" ); document.write( "9=2x+7
\n" ); document.write( "9-7=2x
\n" ); document.write( "2x=2
\n" ); document.write( "x=1
\n" ); document.write( "

\n" ); document.write( "ANS:
\n" ); document.write( "x=1,y=9
\n" ); document.write( "

\n" ); document.write( "Hope this helps,
\n" ); document.write( "best of luck. \n" ); document.write( "

\n" );