document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168174>Question 168174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The wave length (W) of a radio wave varies inversely as its frequency (F).  A wave length with a frequency of 1200 kilohertz has a length of 300 meters.  What is the length of a wave with a frequency of 800 kilohertz? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123942 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The wave length (W) of a radio wave varies inversely as its frequency (F). A wave length with a frequency of 1200 kilohertz has a length of 300 meters. What is the length of a wave with a frequency of 800 kilohertz?<BR>\n" );
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document.write( "W = k/F<BR>\n" );
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document.write( "Find \"k\":<BR>\n" );
document.write( "300 = k/1200<BR>\n" );
document.write( "k = 360000<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "W = 360000/F<BR>\n" );
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document.write( "Find W if f = 800<BR>\n" );
document.write( "W = 360000/800<BR>\n" );
document.write( "W = 450 meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );