document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168149>Question 168149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This one has been answered but the answer does not make sense.  I emailed the tutor and have not heard back.  Will someone please take a look at this for me?<BR>\n" );
document.write( "Thanks\r<BR>\n" );
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document.write( "A square mat has a uniform red border on all four sides.  The rest of the mat is blue.  The width of the blue square is three-fourths the width of the entire square.  If the area colored red is 28 m squared, determine the lengths of each side of the mat. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123917 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A square mat has a uniform red border on all four sides. The rest of the mat is blue. The width of the blue square is three-fourths the width of the entire square. If the area colored red is 28 m squared, determine the lengths of each side of the mat.<BR>\n" );
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document.write( "Let x = length of one side of mat<BR>\n" );
document.write( "and y = width of red border<BR>\n" );
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document.write( "From: \"The width of the blue square is three-fourths the width of the entire square.\" we get equation 1:<BR>\n" );
document.write( "x-2y = (3/4)x<BR>\n" );
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document.write( "From:\"area colored red is 28 m squared\" we get equation 2:<BR>\n" );
document.write( "\"area of mat\" - \"area of blue\" = \"area of red\"<BR>\n" );
document.write( "x^2 - (x-2y)^2 = 28<BR>\n" );
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document.write( "Solve equation 1 for y:<BR>\n" );
document.write( "x-2y = (3/4)x<BR>\n" );
document.write( "-2y = (3/4)x - x<BR>\n" );
document.write( "-2y = -.25x<BR>\n" );
document.write( "y = 0.125x<BR>\n" );
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document.write( "Substitute the above into equation 2 and solve for x:<BR>\n" );
document.write( "x^2 - (x-2y)^2 = 28<BR>\n" );
document.write( "x^2 - (x-2(0.125x))^2 = 28<BR>\n" );
document.write( "x^2 - (x-.25x)^2 = 28<BR>\n" );
document.write( "x^2 - (.75x)^2 = 28<BR>\n" );
document.write( "x^2 - 0.5625x^2 = 28<BR>\n" );
document.write( "0.4375x^2 = 28<BR>\n" );
document.write( "x^2 = 64<BR>\n" );
document.write( "x = (+-)8<BR>\n" );
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document.write( "Well, we can throw out the negative answer leaving:<BR>\n" );
document.write( "x = 8 meters<BR>\n" );
document.write( " </SPAN>\n" );
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